How to Insert Data using AJAX in PHP & MySQL

Tech Area
Last updated on: January 8, 2026

In this tutorial, We will learn how to insert data using AJAX in PHP and MySQL.

Files used in this tutorial:

1- connection.php (database connection file)

2- index.php (registration form and AJAX script)

3- insert-data.php (insert query)

Below are the step by step process of how to insert data into database using Jquery AJAX.

Step 1: Create a Database connection

In this step, create a new file connection.php to create database connection.

connection.php

<?php
$server = "localhost";
$username = "root";
$password = "";
$database = "college_db";
$connection = mysqli_connect("$server","$username","$password");
$select_db = mysqli_select_db($connection, $database);
if(!$select_db)
{
	echo("connection terminated");
}
?>

Step 2: Create Registration form

In this step, create a new file index.php. This is the main file used to implement AJAX to insert data into database with registration form.

This screenshot shows the registration form.

index.php

<html>  
<head>  
    <title>Registration Form</title>  
    <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />  
</head>
<style>
 .box
 {
  width:100%;
  max-width:600px;
  background-color:#f9f9f9;
  border:1px solid #ccc;
  border-radius:5px;
  padding:16px;
  margin:0 auto;
 }
 .error
{
  color: red;
  font-weight: 700;
} 
</style>
<body>  
    <div class="container">  
    <div class="table-responsive">  
    <h3 align="center">Registration Form</h3>
     <div class="box">
      <div class="form-group">
       <label for="name">Enter Your Name</label>
       <input type="text" name="name" id="name" placeholder="Enter Name" class="form-control"/>
      </div>  
       <div class="form-group">
       <label for="email">Enter Your Email</label>
       <input type="text" name="email" id="email" placeholder="Enter Email" class="form-control"/>
      </div>
      <div class="form-group">
       <label for="phone">Enter Your Phone Number</label>
       <input type="text" name="phone" id="phone" placeholder="Enter Phone Number" class="form-control"/>
      </div>
      <div class="form-group">
       <label for="phone">Enter Your Address</label>
       <textarea name="address" id="address" placeholder="Enter Address" required class="form-control"></textarea> 
      </div>
      <div class="form-group">
       <input type="submit" id="register" name="register" value="Submit" class="btn btn-success" />
       </div>
       <p class="error" id="err"></p>
     </div>
   </div>  
  </div>
 </body>  
</html>

Now use jquery AJAX script.

<script src="https://code.jquery.com/jquery-3.7.1.js"></script>
<script type="text/javascript">
  $(document).ready(function(){
    $("#register").on("click", function(e){
      var name = $("#name").val();
      var email = $("#email").val();
      var phone = $("#phone").val();
      var address = $("#address").val();
      $.ajax({
        url: 'insert-data.php',
        method: 'post',
        data: {fullname: name, emailid: email, phone_no: phone, address: address},
        success: function(data){
          $("#err").html(data);
        }
      });
    })
  });
</script>

Step 3: Create new file for insert data

In this step, create a new file insert-data.php. This file used to insert data into database.

insert-data.php

<?php
include('connection.php');
$name = $_POST['fullname'];
$email = $_POST['emailid'];
$phone = $_POST['phone_no'];
$address = $_POST['address'];

$insert_query = mysqli_query($connection, "insert into tbl_registration set name='$name', email='$email', phone='$phone', address='$address'");
if($insert_query>0)
{
	echo "Data submitted successfuly.";
}
else
{
	echo "Error!";
}
?>